Assume That the Two Spheres Can Be Treated as Point Charges. You Can Ignore the Force of Gravity.

Newton's Laws and the Electrical Force

The attractive or repulsive interaction between any two charged objects is an electrical force . Like any force, its effect upon objects is described by Newton'due south laws of motion. The electric force - Felect - joins the long list of other forces that tin can deed upon objects. Newton's laws are applied to clarify the motion (or lack of motion) of objects nether the influence of such a force or combination of forces. The analysis usually begins with the structure of a costless-body diagram in which the type and direction of the private forces are represented by vector arrows and labeled co-ordinate to type. The magnitudes of the forces are so added as vectors in order to make up one's mind the resultant sum, also known as the net force. The net force tin then be used to determine the dispatch of the object.

In some instances, the goal of the analysis is not to determine the acceleration of the object. Instead, the gratis-body diagram is used to determine the spatial separation or charge of two objects that are at static equilibrium. In this case, the free-trunk diagram is combined with an agreement of vector principles in order to determine some unknown quantity in the midst of a puzzle involving geometry, trigonometry and Coulomb'southward constabulary. In this terminal section of Lesson 3, nosotros will explore both types of applications of Newton's laws to static electricity phenomenon.

Electric Force and Acceleration

Suppose that a rubber balloon and a plastic golf game tube are both charged negatively by rubbing them with brute fur. Suppose that the balloon is tossed upwardly into the air and the golf tube is held below information technology in an attempt to levitate the balloon in midair. This goal would exist achieved when the spatial separation between charged objects is adjusted such that the downward gravity strength (Fgrav) and the upwards electrical force (Felect) are balanced. This would present a difficult job of manipulation every bit the airship would constantly motion from side to side and up and down under the influences of both the gravity force and the electrical force. When the golf tube is held too far below the balloon, the airship would fall and accelerate downward. This would in plow decrease the separation distance and lead to an increase in the electric force. Every bit the Felect increases, information technology would likely exceed the Fgrav and the balloon would all of a sudden accelerate up. And finally, if the point of charge on the golf tube is not directly under the point of charge of the balloon (a likely scenario), the electric force would exist exerted at an bending to the vertical and the balloon would have a sideways acceleration. The likely result of such an effort to levitate the airship would exist a diverseness of instantaneous accelerations in a diversity of directions.

Suppose that at some instant in the procedure of trying to levitate the balloon, the post-obit conditions existed:

A 0.90-gram airship with a accuse of -75 nC is located a distance of 12 cm in a higher place a plastic golf tube that has a charge of -83 nC.

How could one utilise Newton'south laws to determine the acceleration of the balloon at this instant?

Like any problem involving force and acceleration, the problem would brainstorm with the construction of a free-body diagram. There are two forces acting upon the airship. The force of gravity on the balloon is directed downward. The electrical force on the balloon is exerted upward since the balloon and golf tube are like-charged and the golf tube is held below the balloon. These two forces are shown in the free-torso diagram at the right. The second stride involves determining the magnitude of these two forces. The force of gravity is determined past multiplying the mass (in kilograms) by the dispatch of gravity.

Fgrav = one thousand • g = (0.00090 kg) • (9.8 m/s/southward)

Fgrav = viii.82 ten 10-3 N, down

The electric force is determined using Coulomb'due south police. As shown beneath, the advisable unit on charge is the Coulomb (C) and the appropriate unit of measurement on distance is meters (chiliad). Use of these units will result in a force unit of the Newton. The demand for these units emerges from the units on Coulomb's constant.

Felect = 1000 • Q1 • Q2 /d2

Felect = (ix x 109 Due north•grand2/C2) • (-75 x x-ix C) • (-83 ten 10-9 C) / (0.12)2

Felect = three.89 x 10-3 N, upwards

The net forcefulness is the vector sum of these two forces. The upward and downward forces are added together equally vectors.

Fcyberspace = ·F = Fgrav (downwards) + Felect (up)

Fnet = 8.82 ten 10-3 N, downward + 3.89 x x-3 Due north, up

Fnet = four.93 x x-3 N, down

The final step of this problem involves the utilize of Newton'south 2nd constabulary to determine the acceleration of the object. The acceleration is the net strength divided by the mass (in kilograms).

a = Fnet / thousand = (4.93 x 10-3 N, down) / (0.00090 kg)

a = v.five m/s/s, downwards

The above analysis illustrates how Newton's law and Coulomb'southward law can exist practical to make up one's mind an instantaneous acceleration. The next analysis involves a case in which two objects are in a state of static equilibrium.

Electric Force and Static Equilibrium

Suppose that two condom balloons are hung from the ceiling by two long strings such that they hang vertically. Then suppose that each balloon is given x average-strength rubs with animal fur. The balloons, having a greater attraction for electrons than animal fur, would larn a negative charge. The balloons would have the same blazon of charge and they would afterward repel each other. The result of their repulsion is that the strings and suspended balloons would at present brand an bending with the vertical. The angle of the string with the vertical would be mathematically related to the quantity of charge on the balloons. As the balloons acquire a greater quantity of charge, the force of repulsion between them would increase and the bending that the string makes with the vertical would also increment. Like any situation involving electrostatic strength, this situation tin be analyzed using vector principles and Newton'south laws.

Suppose that the following weather condition existed.

2 ane.1-gram balloons are suspended from ii.0-meter long strings and hung from the ceiling. They are then rubbed ten times with animal fur to impart an identical accuse Q to each balloon. The balloons repel each other and each string is observed to brand an bending of xv degrees with the vertical. Determine the electric force of repulsion, the accuse on each balloon (assumed to be identical), and the quantity of electrons transferred to each balloon every bit a result of ten rubs with animal fur.

Considering of the complication of the physical situation, it would be wise to stand for it using a diagram. The diagram will serve as a means of identifying the known information for this situation. The diagram below depicts the ii balloons with the string of length L and the angle "theta". The mass ( m ) of the balloons is known; information technology is expressed here in kilogram (the standard unit of mass). The distance between the balloons (a variable in Coulomb'south law) is marked on the diagram and represented by the variable d . The vertical line extending from the pivot point on the ceiling is drawn; this vertical line is one side of a right triangle formed by the horizontal line connecting the balloons and the string extending from airship to ceiling. This right triangle volition be useful as we analyze the situation using vector principles. Notation that the vertical line bisects the line segment connecting the balloons; thus, one side of the right triangle has a distance of d/2 .


The application of Newton's laws to this state of affairs begins with the construction of a free-body diagram for ane of the balloons. In that location are three forces acting upon the balloons: the tension force, the strength of gravity and the electrostatic forcefulness of repulsion. These three forces are represented for the airship on the right. (See diagram beneath.) Note that the tension strength is directed at an angle to the vertical. In physics, such situations are treated past resolving the force vector into horizontal and vertical components. This is shown beneath; the components are labeled every bit Fx and Fy . These components are related to the angle that the string makes with the vertical by trigonometric functions. Since the balloon is at equilibrium, the forces that human action upon the balloon must balance each other. This would hateful that the vertical component of the tension forcefulness ( Fy ) must balance the downward force of gravity ( Fgrav ). And the horizontal component of the tension force ( Fx ) must residual the rightward electrostatic force ( Felect ).


Since the mass of the balloon is known, the force of gravity acting upon it tin can be adamant.

Fgrav = yard •m = (0.0011 kg) • (9.8 1000/south/s)

Fgrav = 0.01078 Due north

The strength of gravity is equal to the vertical component of the tension force (Fy = 0.0108 N ). The Fy component is related to the Ften component and the angle theta by the tangent role. This relationship can exist used to determine the horizontal component of the tension force. The work is shown below.

Tangent(theta) = opposite side/adjacent side

Tangent(theta) = F10 / Fy

Tangent(15 degrees) = F10 / (0.01078 N)

Fx = (0.01078 N) • Tangent(15 degrees)

Fx = 0.00289 N

The horizontal component of the tension force is equal to the electrostatic force. Thus,

Felect = 0.00289 North

Now that the electrostatic strength has been determined using Newton's laws and vector principles, Coulomb's police force tin now exist applied to determine the charge on the balloon.

Information technology is causeless that the balloons accept the same quantity of charge since they are charged in the same mode with ten boilerplate-forcefulness rubs. Since Q1 is equal to Q2, the equation can exist rewritten every bit

This equation can be algebraically rearranged in order to solve for Q. The steps are shown below.

F • d2 = k • Qtwo

Qii = F • d2 / k

Q = SQRT(F • dii / k)

The value of d must be known to complete the solution. This demands that the right triangle exist analyzed in lodge to determine the length of the side contrary the xv-degree angle. This length is half the distance d. Since the length of the hypotenuse is known, the sine function is used.

Sine(Theta) = contrary side / hypotenuse side

Sine(15 degrees) = opposite side / (2.0 chiliad)

opposite side = (2.0 m) • Sine(fifteen degrees)

opposite side = d /2 = 0.518 one thousand

Doubling this distance yields a value of d of 1.035 m. Now substitutions tin can exist made in order to determine the value of Q.

Q = SQRT(F • d2 / thou)

Q = SQRT [(0.00289 N) • (1.035 m)2 / (9 x 109 N•m2/Cii)]

Q = 5.87 x 10-vii C (negative)

The charge on an object is related to the number of backlog (or deficient) electrons in the object. Using the charge of a single electron (-1.six x 10-19 C), the number of electrons on this object tin can be determined:

# excess electrons = (-5.87 10 10-7 C) / (-1.6 x 10-xix C/electron)

# excess electrons = 3.67 ten x12 electrons

During the charging procedure, more than 3 trillion electrons were transferred from the animal fur to each of the balloons. Wow!

Configurations of Three or More Charges

In each of the examples above, nosotros have explored the interaction of 2 charged objects. Newton'south laws and Coulomb's police were combined to clarify the situations. Simply what if there are three or more charges present? Coulomb'south law tin can but consider the interaction between Q1 and Q2. Does the constabulary for electric force accept to exist rewritten to account for a Qiii? No!

Electrical forces result from common interactions between two charges. In situations involving iii or more charges, the electrical force on a unmarried charge is merely the result of the combined furnishings of each private charge interaction of that charge with all other charges. If a item charge encounters ii or more interactions, then the cyberspace electric strength is the vector sum of those private forces. Every bit an instance of this approach, suppose that four charges (A, B, C, and D) are present and that they are spatially bundled to form a foursquare. Charges A and D are both negatively charged and occupy opposite corners of the square and Charges B and C are both positively charged and occupy the remaining two corners as shown. If ane is concerned with the net electrical force acting upon accuse A, then the electrical forces between A and each of the other three charges must be calculated. That is, FBA, FCA and FDA must outset be determined past the application of Coulomb's constabulary to each of these pairs of charges. The notation FBA is used to denote the force of B on A.

FBA = m • QA • QB / dBA 2

FCA = thousand • QA • QC / dCA 2

FDA = k • QA • QD / dDA ii

The direction of each of these iii forces tin be determined by applying the basic rules of charge interaction: oppositely charged objects attract and like-charged objects repel. Applied to this scenario, one would reason that the forces FBA, FCA and FDA are directed as shown in the diagram beneath. Accuse B attracts A and Charge C attracts A since these are pairs of oppositely charged objects. Only Charge D repels A since they are a pair of like-charged objects.


So the magnitudes of the private forces are determined through Coulomb's law calculations. The direction of the individual forces are determined by applying the rules of charge interactions. And once the magnitude and direction of the iii force vectors are known, the 3 vectors can be added using rules of vector addition in order to determine the net electric force. This is illustrated in the diagram higher up.

Cheque Your Understanding

Use your agreement of charge to reply the following questions. When finished, click the button to view the answers.

1. A positively charged object with a charge of +85 nC is being used to balance the downward force of gravity on a 1.8-gram balloon that has a charge of -63 nC. How high in a higher place the airship must the object be held in order to balance the balloon? (Annotation: 1 nC = 1 x 10-nine C)

ii. Airship A and Balloon B are charged in a like manner by rubbing with fauna fur. Each acquires an excess of 25 trillion electrons. If the mass of the balloons is one gram, then how far below Airship B must Balloon A exist held in order to levitate Airship B? Assume the balloons act as point charges.

3. Two 1.2-gram balloons are suspended from light strings attached to the ceiling at the aforementioned point. The net accuse on the balloons is -540 nC. The balloons are distanced 68.2 cm apart when at equilibrium. Determine the length of the string.


4. ZINGER : Three charges are placed along the X-axis. Charge A is a +xviii nC charge placed at the origin. Charge B is a -27 nC charge placed at the 60 cm location. Where along the axis (at what x-coordinate?) must positively charged C be placed in order to be at equilibrium?


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Source: https://www.physicsclassroom.com/class/estatics/Lesson-3/Newton-s-Laws-and-the-Electrical-Force

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